### Class 7 Maths Chapter 2 – Fractions and Decimals Exercise 2.5

**1. Which is greater?**

**(i) 0.5 or 0.05**

**Solution:-**

By comparing whole number, 0 = 0

By comparing the tenths place digit, 5 > 0

∴ 0.5 > 0.05

**(ii) 0.7 or 0.5**

**Solution:-**

By comparing whole number, 0 = 0

By comparing the tenths place digit, 7 > 5

∴ 0.7 > 0.5

**(iii) 7 or 0.7**

**Solution:-**

By comparing whole number, 7 > 0

∴ 7 > 0.7

**(iv) 1.37 or 1.49**

**Solution:-**

By comparing whole number, 1 = 1

By comparing the tenths place digit, 3 < 4

∴ 1.37 < 1.49

**(v) 2.03 or 2.30**

**Solution:-**

By comparing whole number, 2 = 2

By comparing the tenths place digit, 0 < 3

∴ 2.03 < 2.30

**(vi) 0.8 or 0.88**

**Solution:-**

By comparing whole number, 0 = 0

By comparing the tenths place digit, 8 = 8

By comparing the hundredths place digit, 0 < 8

∴ 0.8 < 0.88

**2. Express as rupees as decimals:**

**(i) 7 paise**

**Solution:-**

We know that,

= Rs 1 = 100 paise

= 1 paise = Rs (1/100)

∴ 7 paise = Rs (7/100)

= Rs 0.07

**(ii) 7 rupees 7 paise**

**Solution:-**

We know that,

= Rs 1 = 100 paise

= 1 paise = Rs (1/100)

∴ 7 rupees 7 paise = Rs 7 + Rs (7/100)

= Rs 7 + Rs 0.07

= Rs 7.07

**(iii) 77 rupees 77 paise**

**Solution:-**

We know that,

= Rs 1 = 100 paise

= 1 paise = Rs (1/100)

∴ 77 rupees 77 paise = Rs 77 + Rs (77/100)

= Rs 77 + Rs 0.77

= Rs 77.77

**(iv) 50 paise**

**Solution:-**

We know that,

= Rs 1 = 100 paise

= 1 paise = Rs (1/100)

∴ 50 paise = Rs (50/100)

= Rs 0.50

**(v) 235 paise**

**Solution:-**

We know that,

= Rs 1 = 100 paise

= 1 paise = Rs (1/100)

∴ 235 paise = Rs (235/100)

= Rs 2.35

3. **(i) Express 5 cm in meter and kilometer**

**Solution:-**

We know that,

= 1 meter = 100 cm

Then,

= 1 cm = (1/100) m

= 5 cm = (5/100)

= 0.05 m

Now,

= 1 km = 1000 m

Then,

= 1 m = (1/1000) km

= 0.05 m = (0.05/1000)

= 0. 00005 km

**(i) Express 35 mm in cm, m and km**

**Solution:-**

We know that,

= 1 cm = 10 mm

Then,

= 1 mm = (1/10) cm

= 35 mm = (35/10) cm

= 3.5 cm

And,

= 1 meter = 100 cm

Then,

= 1 cm = (1/100) m

= 3.5 cm = (3.5/100) m

= (35/1000) m

= 0.035 m

Now,

= 1 km = 1000 m

Then,

= 1 m = (1/1000) km

= 0.035 m = (0.035/1000)

= 0. 000035 km

**4. Express in kg:**

**(i) 200 g**

**Solution:-**

We know that,

= 1 kg = 1000 g

Then,

= 1 g = (1/1000) kg

= 200 g = (200/1000) kg

= (2/10)

= 0.2 kg

**(ii) 3470 g**

**Solution:-**

We know that,

= 1 kg = 1000 g

Then,

= 1 g = (1/1000) kg

= 3470 g = (3470/1000) kg

= (3470/100)

= 3.470 kg

**(ii) 4 kg 8 g**

**Solution:-**

We know that,

= 1 kg = 1000 g

Then,

= 1 g = (1/1000) kg

= 4 kg 8 g = 4 kg + (8/1000) kg

= 4 kg + 0.008

= 4.008 kg

**5. Write the following decimal numbers in the expanded form:**

**(i) 20.03**

**Solution:-**

We have,

20.03 = (2 × 10) + (0 × 1) + (0 × (1/10)) + (3 × (1/100))

**(ii) 2.03**

**Solution:-**

We have,

2.03 = (2 × 1) + (0 × (1/10)) + (3 × (1/100))

**(iii) 200.03**

**Solution:-**

We have,

200.03 = (2 × 100) + (0 × 10) + (0 × 1) + (0 × (1/10)) + (3 × (1/100))

**(iv) 2.034**

**Solution:-**

We have,

2.034 = (2 × 1) + (0 × (1/10)) + (3 × (1/100)) + (4 × (1/1000))

**6. Write the place value of 2 in the following decimal numbers:**

**(i) 2.56**

**Solution:-**

From the question, we observe that,

The place value of 2 in 2.56 is ones

**(ii) 21.37**

**Solution:-**

From the question, we observe that,

The place value of 2 in 21.37 is tens

**(iii) 10.25**

**Solution:-**

From the question, we observe that,

The place value of 2 in 10.25 is tenths.

**(iv) 9.42**

**Solution:-**

From the question, we observe that,

The place value of 2 in 9.42 is hundredth.

**(v) 63.352**

**Solution:-**

From the question, we observe that,

The place value of 2 in 63.352 is thousandth.

**7. Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?**

**Solution:-**

From the question, it is given that,

Distance travelled by Dinesh = AB + BC

= 7.5 + 12.7

= 20.2 km

∴Dinesh travelled 20.2 km

Distance travelled by Ayub = AD + DC

= 9.3 + 11.8

= 21.1 km

∴Ayub travelled 21.1km

Clearly, Ayub travelled more distance by = (21.1 – 20.2)

= 0.9 km

∴Ayub travelled 0.9 km more than Dinesh.

**8. Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?**

**Solution:-**

From the question, it is given that,

Fruits bought by Shyama = 5 kg 300 g

= 5 kg + (300/1000) kg

= 5 kg + 0.3 kg

= 5.3 kg

Fruits bought by Sarala = 4 kg 800 g + 4 kg 150 g

= (4 + (800/1000)) + (4 + (150/1000))

= (4 + 0.8) kg + (4 + .150) kg

= 4.8 kg + 4.150kg

= 8.950 kg

So, Sarala bought more fruits.

**9. How much less is 28 km than 42.6 km?**

**Solution:-**

Now, we have to find the difference of 42.6 km and 28 km

42.6

-28.0

14.6

∴ 14.6 km less is 28 km than 42.6 km.