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Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 65+ 45o

= x = 110o

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 60+ 60o

= x = 120o

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 30+ 60o

= x = 90o

2. Find the value of the unknown interior angle x in the following figures:

(i)

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= 70o + x = 100o

By transposing 70o from LHS to RHS it becomes – 70o

= x = 100o – 70o

= x = 30o

(iii)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x + 60o = 120o

By transposing 60o from LHS to RHS it becomes – 60o

= x = 120o – 60o

= x = 60o

(v)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

The given triangle is a right angled triangle. So the angle opposite to the x is 90o.

= x + 35o = 75o

By transposing 35o from LHS to RHS it becomes – 35o

= x = 75o – 35o

= x = 40o