Course Content
Class 10th Science
0/32
Class 10th Maths
0/86
Class 10 Social Science History : India and the Contemporary World – II
0/16
Class 10 Social Science Geography : Contemporary India – II
0/14
Class 10 Social Science Civics (Political Science) : Democratic Politics – II
0/16
Class 10 Social Science Economics: Understanding Economic Development – II
0/10
Class 10 English First Flight Summary
0/22
Class 10 English First Flight Poem
0/22
Class 10 English Footprints without Feet Summary
0/20
Class 10th Online Course: Navigating CBSE Board Success with Wisdom TechSavvy Academy

### Frequently Asked Questions on Chapter 10 – Circles

How many tangents can a circle have?

There can be infinite tangents to a circle. A circle is made up of infinite points which are in a equal distance from a point. Since there are infinite points on the circumference of a circle, infinite tangents can be drawn from them.

Fill in the blanks:A tangent to a circle intersects it in …………… point(s). A line intersecting a circle in two points is called a ………….A circle can have …………… parallel tangents at the most. The common point of a tangent to a circle and the circle is called …………?

A tangent to a circle intersects it in one point(s).A line intersecting a circle in two points is called a secant.A circle can have two parallel tangents at the most.The common point of a tangent to a circle and the circle is called the point of contact.

In a circle, how many tangents can be formed?

There can be infinite tangents to a circle. A circle is made up of infinite points which are at an equal distance from a point.

Since there are infinite points on the circumference of a circle, infinite tangents can be drawn from them.

Find the Length of PQ if a tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm.

Let us consider, the line that is drawn from the centre of the given circle to the tangent PQ is perpendicular to PQ.

And so, OP ⊥ PQ

By using Pythagorean theorem in triangle ΔOPQ we get,

OQ^2 = OP^2 + PQ^2

(12)2 = 52 + PQ2

PQ2 = 144 – 25

PQ2 = 119

PQ = √119 cm

Hence, the length of PQ is √119 cm.