The Work-Energy Theorem for a Variable Force
Example: A body of mass 0.5 kg travels in a straight line with velocity v =a x3/2 where a = 5 m–1/2 s–1. What is the work done by the net force during its displacement from x = 0 to x = 2 m
Solution: We know that WD = Kf – Ki , now we can put value of x=0 in the equation v =a x3/2 to find initial velocity, vi=0, Ki=0,
Similarly find vf by putting x=2, and Kf= ½ mv2 .
- Potential energy is the ‘stored energy’ by virtue of the position or configuration of a body.